(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An incident x-ray has a wavelength of 0.525nm and scatters as 112 degrees above the incidental x-axis in the positive x-direction. Find the direction of propagation of the electron that the incidental wavelength hits. (the answer is to be 34 degrees below the x-axis)

2. Relevant equations

Using Compton's Effect

[tex]\frac{h}{\lambda_{1}}[/tex]=[tex]\frac{h}{\lambda_{2}}[/tex] cos[tex]\theta[/tex]+pecos[tex]\phi[/tex]

0=[tex]\frac{h}{\lambda_{2}}[/tex] sin[tex]\theta[/tex]+pesin[tex]\phi[/tex]

where [tex]\phi[/tex] = angle of electron direction

[tex]\theta[/tex]= angle of x-ray direction

pe=momentum of electron

3. The attempt at a solution

Since the electron momentum is not given, numbers can't be plugged in to find the angle.

Possibly the two equations have to be manipulated together (ie add/subtract) somehow?

Or using energy equations?

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# Homework Help: Who's up for a challenge? Quantum Que

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