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Who's up for a challenge? Quantum Que

  1. Apr 8, 2008 #1
    1. The problem statement, all variables and given/known data
    An incident x-ray has a wavelength of 0.525nm and scatters as 112 degrees above the incidental x-axis in the positive x-direction. Find the direction of propagation of the electron that the incidental wavelength hits. (the answer is to be 34 degrees below the x-axis)


    2. Relevant equations
    Using Compton's Effect
    [tex]\frac{h}{\lambda_{1}}[/tex]=[tex]\frac{h}{\lambda_{2}}[/tex] cos[tex]\theta[/tex]+pecos[tex]\phi[/tex]

    0=[tex]\frac{h}{\lambda_{2}}[/tex] sin[tex]\theta[/tex]+pesin[tex]\phi[/tex]

    where [tex]\phi[/tex] = angle of electron direction
    [tex]\theta[/tex]= angle of x-ray direction
    pe=momentum of electron


    3. The attempt at a solution
    Since the electron momentum is not given, numbers can't be plugged in to find the angle.
    Possibly the two equations have to be manipulated together (ie add/subtract) somehow?
    Or using energy equations?
     
  2. jcsd
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