- #1
amoses7178
- 3
- 0
Why can't "Spooky action" send FTL information?
I understand that for two entangled particles, that if you observe one it will instantly affect the other. I can even understand how we can't make sense of what was observed without sending a "Hey, I got and 'up' what about you?"
But what I don't understand is why information itself can't be sent instantly using this method.
After all, what if you were holding an entangled particle in superposition and you watched it carefully without directly observing it (such as with Wigner's Friend a.k.a the "Quantum Mouse")? Wouldn't the very fact that the particle's wave function collapsed generally give you a clue that its partner had been observed?
And if that's true, what would prevent putting a sequence of entangled particles together so that the wave function collapse or lack there-of encoded a message?
-Alan
I understand that for two entangled particles, that if you observe one it will instantly affect the other. I can even understand how we can't make sense of what was observed without sending a "Hey, I got and 'up' what about you?"
But what I don't understand is why information itself can't be sent instantly using this method.
After all, what if you were holding an entangled particle in superposition and you watched it carefully without directly observing it (such as with Wigner's Friend a.k.a the "Quantum Mouse")? Wouldn't the very fact that the particle's wave function collapsed generally give you a clue that its partner had been observed?
And if that's true, what would prevent putting a sequence of entangled particles together so that the wave function collapse or lack there-of encoded a message?
-Alan