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Why does a gas behave as ideal if the Isotherm and Isenthalp

  1. Apr 25, 2017 #1
    1. The problem statement, all variables and given/known data

    Why does a gas behave as ideal if the Isotherm and Isenthalp are parallel.
    2. Relevant equations
    h=u+pv
    T1=T2, P1V1=P2V2

    3. The attempt at a solution

    h1=u1+p1v1, h2=u2+p2v2
    h2=h1 so
    u1+p1v1=u2+p2v2
    and p1v1=p2v2
    Does that mean internal energy for an ideal gas is zero?
    I don't understand. Thanks in advance!
     
  2. jcsd
  3. Apr 25, 2017 #2
    No. It means that u1=u2
     
  4. Apr 25, 2017 #3
    Thanks! Why would internal energy be equal for an ideal gas process??
     
  5. Apr 25, 2017 #4
    For an ideal gas, the internal energy per unit mass is a unique physical property that depends only on the temperature, irrespective of the process. So, if the temperature is the same, the internal energy is the same.
     
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