- #1

- 94

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## Homework Statement

This isn't necessarily a question but something I found in my notes that I didn't understand.

It says that from

__B__=

__∇__x

__A__one can plug this into Faraday-Lenz's law

__∇__x

__E__= d(

__B__)/dt and it leads to the equation:

__∇__x (

__E__+ d(

__A)__/dt)=0.

From this is says "Using Helmholtz theorem, one can represent the curl free field as the gradient of a scalar potential."

## Homework Equations

__B__=

__∇__x

__A__

__∇__x

__E__= d(

__B__)/dt

__∇__x (

__E__+ d(

__A)__/dt)=0

## The Attempt at a Solution

I know that in electrostatics the curl of the electric field is zero and hence there is a scalar potential associated such that

__E__= -

__∇__V but I don't see the jump for the case involving the vector potential.

Any guidance/explanation would be greatly appreciated.