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Why does this not work? Projectile Motion problem for Dynamics Class
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[QUOTE="haruspex, post: 6848781, member: 334404"] Because there is no solution. As [USER=9587]@robphy[/USER] showed in post #11, the two parabolas do not intersect for t>0. Obtaining what happens to look like a valid solution by deliberately using the wrong equation doesn't sound smart. You avoided all this -y confusion by saying: [LIST] [*]the hill parabola is ##y=-0.04x^2## [*]the landing point is ##(x,y)## [*]the equations of motion are ##y=v\sin(\theta)t-\frac 12gt^2##, ##x=v\cos(\theta)t## [/LIST] which is unarguably correct. When you say "professor", do you just mean teacher, or has this twit actually been awarded a chair? [/QUOTE]
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Why does this not work? Projectile Motion problem for Dynamics Class
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