- #1

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∇-∇Φ=-4πGρ to

∇^2Φ=4πGρ

∇ is divergence, Φ is supposed to be potential energy.

G is gravitational constant and p is density so both are scalars, Any help apreciated.

- Thread starter NotASmurf
- Start date

- #1

- 146

- 2

∇-∇Φ=-4πGρ to

∇^2Φ=4πGρ

∇ is divergence, Φ is supposed to be potential energy.

G is gravitational constant and p is density so both are scalars, Any help apreciated.

- #2

jedishrfu

Mentor

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http://en.wikipedia.org/wiki/Laplace_operator

- #3

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- #4

mathman

Science Advisor

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You misread the previous post. It says "divergence of the gradient is the Laplacian". Don't omit "divergence of".

- #5

HallsofIvy

Science Advisor

Homework Helper

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I suspect that what you are reading as "-", a subtraction, is really "[itex]\cdot[/itex]", a dot product. [itex]\nabla^2 \phi[/itex] is

- #6

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Brilliant! thank you so much, wow I cannot believe I didn't see that, wow.

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