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For car to be able to drive trough banked curve on the road with no friction, the vertical component of a normal force must be equal in size but opposite in direction to the force of gravity.

Horizontal component F[h]

F[h] = m * g * tan(alpha) = m * v^2 / r

So there is only one speed at which F[h] will equal centripetal force at specific angle of the curve and and specific radius.

But why does vertical component of normal force equal the force of gravity when F(h) = m * v^2 / r ?

thanx

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# Homework Help: Why does vertical component of normal force

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