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Advanced Physics Homework Help
Why eigenvalues of L_x^2 and L_z^2 identical?
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[QUOTE="fandango92, post: 4528768, member: 490276"] Sorry I forgot to mention this is for [itex]l=1[/itex]. Okay, but I used [itex]L_z[/itex] eigenvalues of [itex]m\hbar[/itex], where [itex]m=-1,0,1[/itex] in this case, and used [itex]L_x=\frac{1}{2}(L_+ + L_- )[/itex]. I have called the z component the one in which is certain, so how can the x component squared in this case have the same eigenvalues as the z component squared? [/QUOTE]
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Advanced Physics Homework Help
Why eigenvalues of L_x^2 and L_z^2 identical?
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