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## Main Question or Discussion Point

Why are the commutators in QFT

[tex][\phi(x,t),\pi(x',t)]=i\delta (x-x')[/tex]

where pi is the canonically-conjugate momentum density to phi.

Shouldn't a relativistic approach treat time and space more equivalently? Something like

[tex][\phi(x,t),\pi(x',t')]=i\delta (x-x')\delta(t-t')[/tex]

__equal-time__commutators? I am talking about things like[tex][\phi(x,t),\pi(x',t)]=i\delta (x-x')[/tex]

where pi is the canonically-conjugate momentum density to phi.

Shouldn't a relativistic approach treat time and space more equivalently? Something like

[tex][\phi(x,t),\pi(x',t')]=i\delta (x-x')\delta(t-t')[/tex]