- #1
pellman
- 684
- 5
Why are the commutators in QFT equal-time commutators? I am talking about things like
[tex][\phi(x,t),\pi(x',t)]=i\delta (x-x')[/tex]
where pi is the canonically-conjugate momentum density to phi.
Shouldn't a relativistic approach treat time and space more equivalently? Something like
[tex][\phi(x,t),\pi(x',t')]=i\delta (x-x')\delta(t-t')[/tex]
[tex][\phi(x,t),\pi(x',t)]=i\delta (x-x')[/tex]
where pi is the canonically-conjugate momentum density to phi.
Shouldn't a relativistic approach treat time and space more equivalently? Something like
[tex][\phi(x,t),\pi(x',t')]=i\delta (x-x')\delta(t-t')[/tex]