Why is Fourier transform of exp(ix) a delta?

In summary, the Fourier transform of e^{2\pi ikx} is equal to \delta(k) because the delta function is an ideal function that behaves like the delta function.
  • #1
jasonc65
20
0
Why is it that the Fourier transform of [tex] e^{2\pi ikx} [/tex] is equal to [tex] \delta(k) [/tex] ? The delta function is supposed to be zero except at one point. But the integral doesn't converge for [tex] k \ne 0 [/tex]. Yet I see a lot of books on QFT use this identity.
 
Physics news on Phys.org
  • #2
delta isn't a function (what is it at the point where it is not zero?)

It is the delta 'function' because it behaves as the delta function.
 
  • #3
Suppose you were to ask for the Fourier Series for f(x)= cos(x)?

Since the Fourier Series is, by definition, a sum of sines and cosines that add to f(x).
Since f(x)= cos(x), its Fourier series coefficients are just a1= 1, all other coefficients are 0. The delta "function" (it's really a "distribution" or "generalized function") is the functional version of that.
 
  • #4
HallsofIvy said:
Suppose you were to ask for the Fourier Series for f(x)= cos(x)?

Since the Fourier Series is, by definition, a sum of sines and cosines that add to f(x).
Since f(x)= cos(x), its Fourier series coefficients are just a1= 1, all other coefficients are 0. The delta "function" (it's really a "distribution" or "generalized function") is the functional version of that.
Very interesting. The integral [tex] \int^\infty_{-\infty}e^{2\pi ikx} dx [/tex] does in some ways behave like a delta function. And the delta function is an ideal function. However it's own Fourier transform is an exponential, which is a real funtion. The Fourier transform as an operator on Hilbert space is unitary, and squares to -1. Neither the delta function nor the exponential function are in Hilbert space, the latter because it doesn't satisfy boundary conditions, and the former because it isn't even a funtion. The idea is very informal and lacks rigour. I have never seen it given a rigorous basis.
 
  • #5
Then get a book on "distributions" or "generalized functions" everything is done with complete rigor.
 
  • #6
Thanks for the suggestion. :)
 

1. Why is the Fourier transform of exp(ix) a delta function?

The Fourier transform of exp(ix) is a delta function because it represents a pure sinusoidal wave with a frequency of x. This means that all other frequencies are zero, resulting in a single spike at the frequency x in the frequency domain, which is the definition of a delta function.

2. How does the Fourier transform of exp(ix) relate to the properties of the Fourier transform?

The Fourier transform of exp(ix) demonstrates the properties of the Fourier transform, such as linearity, time and frequency shifting, and convolution. It also shows the duality between the time and frequency domains, as the delta function in the frequency domain corresponds to a pure sinusoidal wave in the time domain.

3. What is the significance of the Fourier transform of exp(ix) in signal processing?

The Fourier transform of exp(ix) is essential in signal processing because it allows us to decompose signals into their constituent frequencies. This is useful in analyzing signals, filtering out unwanted frequencies, and designing communication systems.

4. Can the Fourier transform of exp(ix) be generalized to other functions?

Yes, the Fourier transform of exp(ix) is a special case of the Fourier transform and can be generalized to other functions. It is a fundamental tool in mathematics and has various applications in physics, engineering, and other fields.

5. How does the Fourier transform of exp(ix) relate to the concept of orthogonality?

The Fourier transform of exp(ix) is orthogonal to all other functions in the frequency domain, except for multiples of itself. This is because it represents a pure sinusoidal wave with a single frequency, which is orthogonal to all other frequencies. This property is crucial in the analysis of signals and systems, where orthogonality is used to simplify calculations and find unique solutions.

Similar threads

  • Calculus and Beyond Homework Help
Replies
5
Views
342
Replies
2
Views
263
  • Differential Equations
Replies
4
Views
2K
  • Quantum Physics
Replies
4
Views
800
  • Calculus
Replies
4
Views
1K
  • Calculus and Beyond Homework Help
Replies
1
Views
783
Replies
4
Views
282
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
9
Views
686
  • Calculus and Beyond Homework Help
Replies
3
Views
755
Back
Top