Why Is My Integration Approach Not Working?

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The discussion revolves around confusion regarding the integration approach in a mathematical expression. The user struggles to understand how a specific transformation leads to a solvable integral form. They express frustration over a perceived rookie mistake and seek clarification on the correct method. A suggestion is made to differentiate the integration constant to avoid confusion and evaluate the expression at t=0 to identify initial conditions. The conversation highlights the importance of clarity in mathematical notation and the role of integration constants.
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Homework Statement



http://i27.photobucket.com/albums/c171/Chewbacc0r/problem.jpg

The Attempt at a Solution



Basically, for the life of me I can't see how they get from "This expression may be written as..." to "Which may be integrated to contain..."

Now, I have no problem with the integration at all, I just can't see how they've put it in the right form.

Surely;

\frac{1}{v_{0}}+\frac{Ct}{m}= \frac{m+Ctv_{0}}{mv_{0}}

So (\frac{1}{v_{0}}+\frac{Ct}{m})^{-1}=\frac{mv_{0}}{m+Ctv_{0}}

Which integrates to;

\frac{m}{C}ln(m+Ctv_{0}) + C

However as you can see, this is apparently incorrect, and I have a feeling they're right. Just can't see where, I know I'm making a rookie mistake, but I've not practised math for months so it's quite frustrating.

Thanks in advance.

Edit:

I just thought - carrying on using my solution i could simply take \frac{m}{C}ln(m) away from both sides, changing the constant, however that feels like such a cop-out to me, though i guess it would work. I'd still like to know how they've done it if anyone knows.
 
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Chewy0087 said:
Surely;

\frac{1}{v_{0}}+\frac{Ct}{m}= \frac{m+Ctv_{0}}{mv_{0}}

So (\frac{1}{v_{0}}+\frac{Ct}{m})^{-1}=\frac{mv_{0}}{m+Ctv_{0}}

Which integrates to;

\frac{m}{C}ln(m+Ctv_{0}) + C

You've somehow identified the integration constant with C. Pick a different symbol and then evaluate the expression at t=0 to identify x_0.
 
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