- #1

cyberdeathreaper

- 46

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I am asked to find the inverse laplace transform of the following function:

[tex]

\frac{ \left( s+3 \right) }{ \left( s+1 \right) \left( s+2 \right) }

[/tex]

Using tables, can anyone help me understand why the answer is:

[tex]

2e^{-t} - e^{-2t}

[/tex]

I'm completely loss on this one, and yet the book assumes this is easily determined. Any ideas?

Note: I already realize that the bottom can be rewritten using partial fractions, but it seems to me that the book assumes that isn't even necessary - which makes sense, since it doesn't seem to get me anywhere anyway.

[tex]

\frac{ \left( s+3 \right) }{ \left( s+1 \right) \left( s+2 \right) }

[/tex]

Using tables, can anyone help me understand why the answer is:

[tex]

2e^{-t} - e^{-2t}

[/tex]

I'm completely loss on this one, and yet the book assumes this is easily determined. Any ideas?

Note: I already realize that the bottom can be rewritten using partial fractions, but it seems to me that the book assumes that isn't even necessary - which makes sense, since it doesn't seem to get me anywhere anyway.

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