I have two questions. Both questions are in the picture below. Dont mind my workings lol
Ans to the 1st qn: C
The potential difference across the 3ohm resistor is zero. Thus, it can be considered that the 4ohm and 2 ohm resistor is in parallel with the 8ohm and 4 ohm resistor. So the effective resistance between A and B is
(1/(4+2) +1/(8+4))^-1 = 4ohms
But my question is, why is the p.d. across 3 ohm resistor zero?
Ans to the 2nd qn: C
The effective e.m.f is 1.5v and effective internal resistance is (1/3 + 1/3+1/3)^-1 = 1ohms
1.5=I(10 + 1)
And my question is, how does the circuit work? Why do we have the consider all of the internal resistance of the batteries?
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