- #1
Lars278
- 8
- 1
The Swing Weight of a golfclub = m * (r - 14)
m = mass of the club in grams
r = distance from the top of the shaft to the center of mass of the club in inches
6050 equals the swing weight D-0
But the formula for the angular acceleration of any object spinning around an axis is:
ωdot = τ / I
In the case of a thin rod spinning around one of it's endpoints this will be:
ωdot = 3 * τ / (m * r2)
m, and r are now in SI units though. (kg and meters)
But in the formula for swing weight there is no r2 only an r. Why is this?
m = mass of the club in grams
r = distance from the top of the shaft to the center of mass of the club in inches
6050 equals the swing weight D-0
But the formula for the angular acceleration of any object spinning around an axis is:
ωdot = τ / I
In the case of a thin rod spinning around one of it's endpoints this will be:
ωdot = 3 * τ / (m * r2)
m, and r are now in SI units though. (kg and meters)
But in the formula for swing weight there is no r2 only an r. Why is this?
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