Why is this flux negative and not postiive?

  • Thread starter mr_coffee
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  • #1
mr_coffee
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Hello again. The first problem I even came close to getting right, and yet i still missed it by a negative sign. There is a square surface measures 3.2mm on each side. It is immersed in a uniform elelctric field with magnitude E = 1800 N/C and with field lines at an angle of 35 degrees with normal to surface, as shown. Take that normal to be directed "outward" as though the surface were one face of a box. Calculate the electric flux through the surface.

So I used Flux = E cos(35)A; Plugged and chugged and got Flux = .015 Nm^2/C. The answer in the back of the book is Flux = -.015 Nm^2/C. Why would it be negative? If u need the image tell me and i'll scan it. It looks like a top of a box. Normal is straight up from the boxes surface pointing to the sky. the elctrical field lines are going through the box South Westward, you know if u draw a heart and put an arrow through it, that's what the lines look like they are doing.
 

Answers and Replies

  • #2
Doc Al
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Careful when you "plug and chug". Remember that if the field points out of the surface (in the same direction as the normal) then the flux is positive; in this case the field points into the surface. Your formula would work if you used the angle that the field makes with the normal vector: that angle is 145 degrees, not 35 degrees. (Draw a picture.) It makes an angle of 35 degrees with the negative of the normal vector, which is 180 degrees away from the positive normal vector.

I recommend that you use the formula to get the magnitude of the flux but use a picture (and the rule I gave above) to find the sign of the flux.
 

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