- #1
Artusartos
- 247
- 0
Homework Statement
If we have [tex]R = \{ \frac{1}{2}(a+b\sqrt{2}) \}[/tex].Homework Equations
The Attempt at a Solution
For the identity, we have a=2 and b=0. So the identity is not equal to zero. Also, there can't be any zero divisors, because...
[tex][\frac{1}{2}(a+b\sqrt{2})][\frac{1}{2}(a'+b'\sqrt{2})] [/tex] = [tex]\frac{1}{4}(aa' + ab'\sqrt{2} + a'b\sqrt{2} + 2bb')[/tex]. If a,a',b, b' are not zero, then this can't be zero.
So why isn't it a domain?
Thanks in advance
Last edited by a moderator: