Weinberg's Cosmology: Neglecting (1+z(eq)) in Denominator

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In summary, Weinberg's Cosmology is a theoretical framework based on general relativity that explains the structure and evolution of the universe. Neglecting (1+z(eq)) in the denominator is a simplifying assumption often made in calculations, as it does not significantly affect the results. However, (1+z(eq)) is used to calculate the energy density of the universe at the time of matter-radiation equality, marking a key point in its evolution. While neglecting this term may introduce some error, it does not significantly affect the predictions and conclusions of Weinberg's Cosmology.
  • #1
EhsanZ
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In equation below
〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))

Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?

Weinburg did it in his book named "Cosmology".
 
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  • #2
I would assume that z is incredibly close to 0.
 
  • #3
EhsanZ said:
Weinburg did it in his book named "Cosmology".

I would like to see the context, but I don't feel like looking for this by flipping through Weinberg page-by-page. Could you please give the page number?
 

1. What is Weinberg's Cosmology?

Weinberg's Cosmology is a theoretical framework that attempts to explain the structure and evolution of the universe. It is based on the principles of general relativity and assumes a homogeneous and isotropic universe on large scales.

2. What does it mean to "neglect (1+z(eq)) in denominator" in Weinberg's Cosmology?

In Weinberg's Cosmology, (1+z(eq)) refers to the redshift of the universe at the time of matter-radiation equality. Neglecting it in the denominator is a simplifying assumption that is often made in calculations, as it does not significantly affect the overall results.

3. What is the significance of (1+z(eq)) in Weinberg's Cosmology?

In Weinberg's Cosmology, (1+z(eq)) is used to calculate the energy density of the universe at the time of matter-radiation equality. This is important because it marks a key point in the evolution of the universe, when matter became the dominant component and began to drive its expansion.

4. What are the implications of neglecting (1+z(eq)) in Weinberg's Cosmology?

Neglecting (1+z(eq)) in the denominator may introduce some error in calculations, but it is considered a minor approximation in most cases. However, in more precise calculations, it may be necessary to include this term for more accurate results.

5. How does neglecting (1+z(eq)) affect the predictions of Weinberg's Cosmology?

Neglecting (1+z(eq)) in the denominator does not significantly affect the overall predictions and conclusions of Weinberg's Cosmology. It is often a simplifying assumption that allows for easier calculations and does not change the overall understanding of the structure and evolution of the universe.

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