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Why negligible?

  1. Dec 20, 2011 #1
    In equation below
    〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))

    Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?

    Weinburg did it in his book named "Cosmology".
     
  2. jcsd
  3. Dec 20, 2011 #2
    I would assume that z is incredibly close to 0.
     
  4. Dec 20, 2011 #3

    George Jones

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    I would like to see the context, but I don't feel like looking for this by flipping through Weinberg page-by-page. Could you please give the page number?
     
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