The proton is composed of two up quarks and one down quark. Its total number of H+ is 11 and H- is 5. As a rule, the maximum number of H’s in each LOE (level of existence) is eight. The proton exists in the 2nd LOE (complete). For the composite neutron, 1 up quark and 2 down quarks, its total number of H+ is 7 and H- is 7. Its 1st LOE is filled while its 2nd LOE needs two more space charges to complete. Using the ratio of the mass of proton to that of the neutron, one can calculate that the strength of H- for these nucleons is 2.012588 stronger than that of H+. The mass of the proton in SI units is given as 1.673x10^-27 kg and the mass of the neutron is given as 1.675x10^-27 kg. The following simultaneous equations can be solved for the strength of H+ and H-. 11H+ + 5H- = 1.673 x 10^-27 7H+ + 7H- = 1.675 x 10^-27 H- =0.159857 x 10^-27, H+ =0.079429 x 10^-27. The electron is given by 7 H- and 1 H+. The electron has its 1st LOE complete. The proton is 1836 times heavier than the electron. This means that mass is in direct proportion to the level of LOE. Higher the LOE, the heavier is the particle and the more space charges. These calculations ignored other unknown factors.