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(-3)² = ([tex]\sqrt{9}[/tex])² --> True
-3 = [tex]\sqrt{9}[/tex] --> False
Wolfram Alpha result: False
-3 = [tex]\sqrt{9}[/tex] --> False
Wolfram Alpha result: False
Last edited:
Really? In my classes, we've always used [tex]\sqrt[]{x^{2}}=\pm x[/tex]The square root of x is defined as the unique POSITIVE number who's square is x.
No, this is wrong. The square root function is defined to be the unique positive square root of the number. [tex]\sqrt{9}=3[/tex] and if [tex]\sqrt{9}=\pm3[/tex] then I have no clue why we would write such answers as [tex]x^2=9 \rightarrow x=\pm \sqrt{9}[/tex] when the square root is already [tex]\pm[/tex]When you "undo" a squared operation, it is not as simple as just removing the little "2" superscript.
Really? In my classes, we've always used [tex]\sqrt[]{x^{2}}=\pm x[/tex]