Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Wick rotation and Minkowski/Euclidean space

  1. Feb 10, 2013 #1
    Hello, I was wondering why in integrals such as
    \int d^4k F(k^2)
    where [tex] k^2 = (k^0)^2 - |\vec{k}|^2 [/tex] ranges from -∞ to ∞, once the Wick-rotation is performed, we have [tex] -k^2_E = -(k^0_E)^2 - |\vec{k}_E|^2 [/tex] which lies in the (-∞,0) interval ... So, the contribution which lies in the part where [tex] k^2 >0[/tex] it seems that fades away. This function would have even poles. It is still a bit counter-intuitive for me that this part just fades away.

    I guess we could shift the space-variables as [tex] \vec{k} \rightarrow \vec{k+k_0} [/tex] so this always lays in the euclidean space so to say. Anyway I am not sure, if this shift is always allowed.

    Asides, things get more annoying for me if we have other four-vectors in the function, appart that the loop variable, which are Minkowskian, i.e. [tex] F((k+q)^2,(k-p)^2) [/tex] where [tex] q^2 = m^2, \ p^2 = M^2 [/tex] (both are positive quantities) ...

    I find this kind of examples in triangle loops diagrams where the function F(k,q,..) is the form factor, and I this form factor is supposed to be the in the Spacelike or Euclidean region ...

    Thanks in advance!
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted