Wierd Q to take a derivative of

  • #1

Main Question or Discussion Point

wierd Q to take a derivative of....

y=(x)/((x+2)(x+3)(x+4)).
how to do u take the derivative??? HELP!!!!!! :confused:
 

Answers and Replies

  • #2
dextercioby
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So is it

[tex] y(x)=\frac{x}{(x+2)(x+3)(x+4)} [/tex]

Do u know to apply the

1.Quotient's derivative rule.
2.Leibniz product rule...?

Daniel.
 
  • #3
arildno
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AARGH!!!!!!!!!!!!!!!!!!!!!!!!!

DO NOT DOUBLE, TRIPLE, OR QUADRUPLE POST IN THE FUTURE!!!!!!!!!!!!!!!!!!!!!
:grumpy:
 
  • #4
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The easiest way would be to rewrite it like this first:

y=(x) * (x+2)(^-1) * (x+3)(^-1) * (x+4)(^-1)
 
  • #5
haha, i guess i'd get mroe help dat way, but, oops hehe
 
  • #6
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the easiest way is actually probably to just multiply out the denominator:

[tex]\frac{x}{(x+2)(x+3)(x+4)} = \frac{x}{x^3 + 9x^2 + 26x + 24}[/tex]

and then just use the product rule and the fact that

[tex]\frac{d}{dx}\frac{1}{f(x)} = -\frac{f^\prime (x)}{\left[f(x)\right]^2}[/tex]
 
  • #7
arildno
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the4thcafeavenue said:
haha, i guess i'd get mroe help dat way, but, oops hehe
At least, now you've learnt your lesson, right? :wink:
 

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