There is no torque about its center of mass (on which point I agree with @CWatters). So it will not spin.

More generally, it will slide if its linear acceleration exceeds its rotational acceleration multiplied by its radius. Since its rotational acceleration is zero and its linear acceleration is non-zero, this condition is trivially met. You would typically determine the two accelerations by drawing free body diagrams, determining relevant forces and solving the resulting equations.