Will someone hit this softball out of the park?

1. Jan 22, 2005

feveredego

What are the odds of something that statistically should happen 1 in 207 times happening 3 times in 66 occurrences? Let me know.

2. Jan 22, 2005

arildno

$$p=\binom{66}{3}(\frac{1}{207})^{3}(\frac{206}{207})^{63}\approx\frac{1}{263}$$
The probability for a single, specific arrangement is $$(\frac{1}{207})^{3}(\frac{206}{207})^{63}$$
the binomial coefficient tells us how many such arrangements exist (in your case, 45760 different arrangements of 3 "hits" and 63 "misses")
Welcome to PF!

Last edited: Jan 22, 2005