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Will someone hit this softball out of the park?

  1. Jan 22, 2005 #1
    What are the odds of something that statistically should happen 1 in 207 times happening 3 times in 66 occurrences? Let me know.
     
  2. jcsd
  3. Jan 22, 2005 #2

    arildno

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    Short answer:
    [tex]p=\binom{66}{3}(\frac{1}{207})^{3}(\frac{206}{207})^{63}\approx\frac{1}{263}[/tex]
    The probability for a single, specific arrangement is [tex](\frac{1}{207})^{3}(\frac{206}{207})^{63}[/tex]
    the binomial coefficient tells us how many such arrangements exist (in your case, 45760 different arrangements of 3 "hits" and 63 "misses")
    Welcome to PF!
     
    Last edited: Jan 22, 2005
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