Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Will they collide? No but

  1. Sep 15, 2004 #1
    Two trains heading straight for each other on the same track are 250 m apart when their engineers see each other and hit the brakes. The A, heading west at 96 km/h, slows down, accelerating at an average of -4 m/s^2, while the B, traveling at 110 km/h, slows down, accelerating at an average of -3 m/s^2. Will they collide?


    I solved it this way :
    a_T = The resultant of two accelerations = -7
    V_A = 96 km/h
    V_B = 110 km/h
    V_T = V_B + V_A = 206 km/h = 57.22 m/s
    And considered (V_T)_final = 0.
    Plugging into this formula : S = - [(V_T)^2 ] / 2 a_T; S = 233.9. So two trains won't collide.
    My answer for S is not the same as the one in the solutions manual, 244.5 m. Why is my answer 233.9 ?
    The book has solved that problem in a different way, and I can do it so, but I'm interested to know why my answer is wrong.
     
  2. jcsd
  3. Sep 15, 2004 #2

    HallsofIvy

    User Avatar
    Science Advisor

    The two trains do not decelerate for the same length of time.

    The train moving at 96 kph = 26.67 m/s decelerates at -4 m/s2 for 26.67/4= 6.67 seconds at which time it is stopped. The train moving at 110 kph= 30.5 m/s decelerates at -3 m/s2 for 30.5/3= 10.18 seconds. The two trains will have a "relative deceleration" of -7 m/s2 for the first 6.67 seconds but after that the first train has stopped and the "relative deceleration" is only -3 m/s2. You could do the problem by considering those to time intervals separately but it is easier to treat the two trains separately- which is what I presume you book did- that's what I did and got the same answer as your book.
     
  4. Sep 15, 2004 #3
    Thank you

    Ok.
    What if two accelerations were equal ?
    Thank you
     
  5. Sep 15, 2004 #4

    BobG

    User Avatar
    Science Advisor
    Homework Helper

    If the accelerations were equal, your approach would be fine. In fact, if you substituted a force that could send the train in reverse (thrusters or spin the wheels backward, for example), your approach would be fine, provided you subtracted your answer from the 250 m to find out how close the trains would come to each other.

    Your answer was wrong because of the special case given - brakes can only slow you down to 0, they can't send you into reverse.
     
  6. Sep 15, 2004 #5

    Chronos

    User Avatar
    Science Advisor
    Gold Member

    Break problem into two parts. First solve for a final velocity of 0 for each train using the formula Vf = Vi + AT and solve for T for each train. Next, plug T for each train into the distance formula D = AT^2/2. Next add up the distance each train travels.
     
    Last edited: Sep 15, 2004
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook