Winding Dilemma

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1. Jun 2, 2017

Entrepreneur

I attach an image of something I am experimenting with.

The picture itself (and added text) should be self-explanatory.

1) Which way should my windings (clockwise or counter-clockwise) go around P1; P2; P3 & P4 for maximum voltage (V) ?
[ 1 Ø ]
[ 1 x single enamelled copper conductor ]
[ 2.5mm² ]
[ 65 turns per P1 - P4 each ]
[rotational speed = 9 revs/sec]

2) Is there a method of calculating Vmax & I max outputs from the above ?

3) Feel free to email me at # # # # at # # # # dot com

Last edited by a moderator: Jun 2, 2017
2. Jun 3, 2017

Baluncore

Is it supposed to be a two phase alternator? Will you rectify the AC from the windings to produce DC?
If so, the gaps between the poles are much wider than sensible. Better utilisation of materials if closer together.
The coils should be on the stator, not the rotor. The coils will tend to be thrown off that rotor, so better to have a magnet that rotates with stationary windings and no slip rings.
At low RPM you will need many more poles. Fisher & Paykel smartdrive washing machines have 48 poles.

3. Jun 4, 2017

Entrepreneur

1 Ø = single phase (given)
Yes, but AC rectification is not important at this stage (in Question 2 Vrms & Irms still need to be calculated)
the gaps between poles are not important at this stage
the coils ARE on the stator (rotating outer cylinder with magnets = rotor)
stator is where the windings are (P1 - P4) (stationary)

So back to my question :
Which way should my windings (clockwise or counter-clockwise) go around P1; P2; P3 & P4 for maximum voltage (V) ?

4. Jun 4, 2017

Baluncore

Vmax will be dependent on the number of turns per pole, the spacing and dimensions of the poles, the strength of the magnets and the specified RPM.
Your rotor and stator seem to be designed to produce two phases.

5. Jun 4, 2017

Entrepreneur

Yeah, it may look like it ?

So I guess you don't know about the winding direction ?

6. Jun 4, 2017

jim hardy

Six pole stator, four pole rotor..... sounds more like a stepper motor than a generator.

What does right hand rule tell you ?

7. Jun 4, 2017

Baluncore

I know it cannot be wound sensibly as a single phase alternator.

8. Jun 5, 2017

Entrepreneur

I concede - it cannot be wound as a sensible alternator / generator, but that is all I have to work with.

A 6-pole rotor and a 4-pole stator.

9. Jun 5, 2017

Entrepreneur

Jim, the rotor is the outer part. [6-pole rotor & 4 pole stator.]

The 6 x neodymium magnets are fixed to the inside of a cylinder which rotates (9 rev/s or 540 rev/m) around the 4-pole stator which is fixed on a shaft.

OPTION A
The idea is to get the maximum voltage and current (within limitations) from this configuration (preferably single phase).
At this stage my stator is wound CCW-CW-CCW-CW and I get between 10Vrms & 15Vrms from the output - but the moment I put a load (10V globe) the output halves. I suspect that the windings at present is wrong and that a configuration of CW-CW-CCW-CCW would be more suited.

OPTION B
I suppose building a new alternator / generator would be the ideal (discarding the 4-pole stator & 6-pole magnet), but I would be limited by the rotation speed, diameter size of cylinder (usable stator plate size between shaft & inner cylinder). Rectification of the Vac is only done after I can establish a decent voltage and current output.

Your thoughts (and Baluncore's) would be appreciated.

10. Jun 5, 2017

Asymptotic

Out of curiosity, what is a 10V globe? What was the loaded voltage, and how much current was flowing?

11. Jun 5, 2017

Entrepreneur

Yes, I was as surprised as you are - my wife happened to find a small incandescent 10Vac globe. The loaded (output V) was 8.5Vac - made the globe glow - when I measured the V while glowing it was 4.5V ?

12. Jun 5, 2017

Entrepreneur

i didn't measure AC current because of the limitations of my multimeter.

13. Jun 5, 2017

Asymptotic

Incandescent lamp resistance is very non-linear. When the filament is cold, resistance is only a few ohms, and it rises to a much higher value at full temperature. Voltage collapse suggests more current is flowing than the alternator as presently configured can provide.

14. Jun 5, 2017

Entrepreneur

Totally off topic, but interesting nonetheless. Thank you.

15. Jun 5, 2017

Asymptotic

Your alternator load is an incandescent lamp. In what way is it off topic to consider how an incandescent lamp operates?

For example, filament resistance of a 100W, 120V tungsten bulb is approximately 144 ohms (I=E/R, 0.83 amps. R=E/I, 144 ohms) at normal operating temperature. Measured filament resistance at room temperature is 9.5 ohms. When 120V is connected to it, for a very brief time (in the low millisecond range) current surge approaches 120V/9.5 ohms (12.6 amps), then as the tungsten heats up, resistance increases, and current drops off.

You didn't provide the test lamp's power rating. For example, if it is 10 watts, then current will be 1 amp (I=P/E, 10W/10V = 1A), with a hot resistance of R=E/I = 10/1 = 10 ohms. Resistance decreases, and current demand increases the closer the filament gets to room temperature (where it is probably less than an ohm).
What was the difference between when output was 8.5V, and when it was 4.5V?

If your multimeter doesn't have an AC current range then wire a small value power resistor in series with the load, measure voltage drop across it, and calculate load current using Ohm's law. For instance, a 0.1 ohm, 10 watt resistor will drop 500 mV across it at 5 amps of current flow (E=IR, 5A*0.1Ω = 0.5V).

16. Jun 5, 2017

Baluncore

Then wind it as a two phase alternator, with (P1+P3) and (P2+P4).
Rectify each phase independently with a bridge rectifier, sum the DC outputs by connecting the DC outputs in parallel.
The DC output voltage will not fall to zero like a rectified single phase alternator.

17. Jun 5, 2017

CWatters

How are you viewing the coils and how are they connected together? Can you mark up the drawing?

18. Jun 5, 2017

jim hardy

Here's the thought line i was playing with

There will be leakage flux through tips of P2 & P4 , between adjacent magnets, that i didnt draw because it won't couple your windings.

so it seems there's likelihood it'd work as pair of two pole rotors.
Connect opposing poles in series , wound same direction. Note a single winding is CW looking into one end, CCW looking into the other.

Energy conversion will flip-flop between even and odd poles.

I think that's what you have .

I'd sure like to see the waveform that thing makes. Have you an oscilloscope?

old jim

19. Jun 7, 2017

Entrepreneur

Didn't consider that - good tip!

20. Jun 7, 2017

Entrepreneur

Sound like a do-able idea - thanks!