- #1

pythagoras88

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Does a straight wire in changing B field(the field is perpendicular to the wire) has an induced emf?

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- Thread starter pythagoras88
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- #1

pythagoras88

- 17

- 0

Does a straight wire in changing B field(the field is perpendicular to the wire) has an induced emf?

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Born2bwire

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- #3

pythagoras88

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E=-s/2. dB/dt.[tex]\phi\widehat{}[/tex]. Assuming the B field is uniform throughout the plane, and is changing at constant rate. So, if the square loop is put at a distance from the center of the field, then the induced E field in it seems to be different as E has the dependence on s. Thus, result in a seemingly difference emf induced if the loop is placed at different region.

However, from faraday's law, [tex]\epsilon[/tex]=-d[tex]\Phi[/tex]/dt. Since the area enclosed by the loop is the same plus the rate of change of B field is the same, it implies that the emf induced is the same in the loop no matter where it is placed in the B field.

hmm... why there seems to be a contradiction?

Sorry for the long winded qn!

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