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J89
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Homework Statement
A copper wire is 9.00 m long and has a cross-sectional area of 1.00 10-4 m2. This wire forms a one turn loop in the shape of a square and is then connected to a battery that applies a potential difference of 0.100 V. If the loop is placed in a uniform magnetic field of magnitude 0.600 T, what is the maximum torque that can act on it? The resistivity of copper is 1.7 10-8 · m.
Homework Equations
T=BIANsin(theta)
I=V/R
The Attempt at a Solution
First solve for R, whicn =
Resistivity*L/A = 1.7e-8*9/(1e-4)
= .00153 ohms
then solve for current (I) = I=V/R = .100/.00153 = 65.359
Then plug in the equation for torque = T=NBIAsin(theta)
however I got.00392, but it's wrong, the answer is 198.53..I know it has something to do with A, but don't know what. Someone please help!