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lemon
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Homework Statement
A wire of diameter 5.0 mm supports a 2.8kg load.
(a) Determine the tension in the wire
(b) The original length of the wire was 2.0m Calculate its extension when supporting the load.
Homework Equations
Young's modulus for the material of the wire = 2.0 x 10^7N m^-2
The Attempt at a Solution
a) Tension - Weight = mass x acceleration
acceleration is 0
Therefore
Tension = Weight
W=mg=2.8 x 10
=28N
b) I have the equation E=(force(F)/area(A)) / (extension(ex)/original length(l))
Can I:
(F x ex) = (A x l)
ex= (A x l)/F?
Which would give ((2.5x10^-3)x2.0) / 28 = 0.18x10^-3m (2s.f.)
Please let me know if my method is good?
Thank you