(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A wire of diameter 5.0 mm supports a 2.8kg load.

(a) Determine the tension in the wire

(b) The original length of the wire was 2.0m Calculate its extension when supporting the load.

2. Relevant equations

Young's modulus for the material of the wire = 2.0 x 10^7N m^-2

3. The attempt at a solution

a) Tension - Weight = mass x acceleration

acceleration is 0

Therefore

Tension = Weight

W=mg=2.8 x 10

=28N

b) I have the equation E=(force(F)/area(A)) / (extension(ex)/original length(l))

Can I:

(F x ex) = (A x l)

ex= (A x l)/F?

Which would give ((2.5x10^-3)x2.0) / 28 = 0.18x10^-3m (2s.f.)

Please let me know if my method is good?

Thank you

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# Homework Help: Wire tension and extension

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