ooooooXXXXR2XXXXXR3XXXX XXR1XXoooooooooooooooooXXXXX XooooXoooooooooooooooooXooooX XooooXXXXR4XXXXXXR5XXXXoooX XoooooooooooooooooooooooooooX XoooooooooooooooooooooooooooX XoooooooooooooooooooooooooooX XXXXXXXXX+BATTERY-XXXXXXXXX X=WIRE o= blank space (ignore) R=resistor battery= 9 V Determine the power dissipated in the R4 resistor in the circuit shown in the drawing. R1=3 ohms R2=2 ohms R3=1 ohms R4=6 ohms R5=1 ohms So here is what i know so far. The resistance of R4+R5=7. The resistance of R2+R3=3. So the resistance of R2345=1/(1/7+1/3)=2.1 ohms. The total resistance through the entire circuit is R1+R2345=3+2.1=5.1 ohms. So I use this total resistance to calculate the total current I=V/R so I=9V/5.1ohms=1.76A. Now I can use this total current to calculate the voltage across R4 and R5. V=IR=1.76(2.1)=3.7 V across R4 and R5 since Voltage across parallel circuits are the same. I know power=IR^2=V^2/R. But i cannot just plug in 3.7V^2/6ohms. This isnt giving me the right answer. I need to find the voltage across R4 only. I am not sure how to do this since the current is different passing through each resistor. please help and correct me if any of the previous steps i did were wrong. thanks.