Hi,(adsbygoogle = window.adsbygoogle || []).push({});

This is just a quick question -- I'm puzzled by the way this answer sheet represents the potential function.

The question asks us to determine the energy eigenvalues of the bound states of a well where the potential drops abruptly from zero to a depth Vo at x=0, and then increases linearly with position x until at x=a the potential is again zero.

They write:

[tex]V(x) = \frac{V_{0}x}{a}[/tex]

[tex]E = V(b) = \frac{V_{0}b}{a}[/tex]

where b is some point between x=0 and x=a.

But surely the correct representation of the potential function is

[tex]V(x) = V_{0}\left(\frac{x}{a}-1\right)[/tex]

so that V(0) = -Vo, and V(a) = 0. But, using my potential function, I end up with a somewhat different expression for the energy eigenvalues, in the end, than they do. Why do they do it that way? And what's wrong with my pot. function??

Cheers!

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# Homework Help: WKB eigenvalue problem

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