# Wondering where the distance formula from acceleration due to gravity comes from

Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.

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If a=g, then integrate twice with respect to time !!

Tom Mattson
Staff Emeritus
$$\frac{d^2y}{dt^2}=-g$$
$$y(0)=0$$
$$y'(0)=0$$.