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Wondering where the distance formula from acceleration due to gravity comes from

  1. Sep 13, 2005 #1
    Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
     
  2. jcsd
  3. Sep 13, 2005 #2
    If a=g, then integrate twice with respect to time !!
     
  4. Sep 16, 2005 #3

    Tom Mattson

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    That's almost right. When you integrate twice you pick up two arbitrary constants of integration. To really derive the formula you would have to solve the following initial value problem:

    [tex]\frac{d^2y}{dt^2}=-g[/tex]

    [tex]y(0)=0[/tex]

    [tex]y'(0)=0[/tex].
     
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