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Wondering where the distance formula from acceleration due to gravity comes from

  1. Sep 13, 2005 #1
    Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
  2. jcsd
  3. Sep 13, 2005 #2
    If a=g, then integrate twice with respect to time !!
  4. Sep 16, 2005 #3

    Tom Mattson

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    That's almost right. When you integrate twice you pick up two arbitrary constants of integration. To really derive the formula you would have to solve the following initial value problem:



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