What is the change in horizontal distance from low tide to high tide?

In summary, a cargo ship is tied up at the dock. At low tide, a 12-m long unloading ramp slopes down from the ship to the dock and makes an angle of 30 degrees to the horizontal. At high tide, the ship is closer to the dock, and the unloading ramp makes an angle of 45 degrees t othe horizontal. The change in the horizontal distance from the ship to the dock from low tide to high tide is 6 meters.
  • #1
Nelo
215
0

Homework Statement


A cargo ship is tied up at the dock. At low tide, a 12-m long unloading ramp slopes down from the ship to the dock and makes an angle of 30 degrees to the horizontal. At high tide, the ship is closer to the dock, and the unloading ramp makes an angle of 45 degrees t othe horizontal.

a) Determine the change in the horizontal distance from the ship to the dock from low tide to high tide. Express the distance as an exact value and as an approximate value


Homework Equations





The Attempt at a Solution



So, looking at the angles i determined that both of these angles are in relation to the exact trig ratio triangles.

I know taht the answer is 6([sqrt3 - [sqrt] 2 ) but I don't know the steps.

I know that the first triangle, which is the one at 60 degrees has a height of [sqrt]3 , and the second one has a slant height of the [sqrt] 2, But where does the 6 come from? and how does the 12-m long unloading ramp come into play in this problem?
 
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  • #2
anyone?
 
  • #3
You might want to draw a diagram and use the appropriate trigonometric ratios then.
 
  • #4
wat...?
 
  • #5
Did you draw a diagram showing all information in the problem? If so, post it here, and if not, draw one and then post it.
 
  • #7
Why do you have two diagrams? The situation only needs one. Also I don't think you included the length correctly, see the image attached. AD=BD=Ramp Length
 

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  • #8
k well, here's a dif one.

If 0º<A<360º

Find all measures of <A

g) Cos A = - [sqr3] / 2

I took the - sqr of 3 /2 and got 150. so that's one possible value.

That point lies somewhere in the second quadrant. If you do 180-150 *since its still in the second quadrant) you get 30. however the answer is 220 for some reason, why is that? why do you do 360 - 150 to get that answer .
 
  • #9
Cosine is negative in the second and third quadrants. It would be beneficial to note that

cos(90+A)= -sin(A)
cos(180+A)= -cos(A)

The value in third quadrant is not 220. Use the above to figure it out. Also at 30 degrees cosine is positive, not negative.
 
  • #10
210... So you subtracted 360 becasue it is positive in the final quadrant?
 
  • #11
Right.
 
  • #12
Sin A = -0.5

Took the inverse of that and got sin = -30, and since sin is pos in the second quadrant and its moving clockwise i subtracted 270 from that and got 240.. but the answer is 210, 330. how..?
 
  • #13
So when its negetive you add 180 to that negetive value and the get the counterclockwise quadrant. then you start from "all" or quadrant 1 and see where cos becomes positive and subtract from there, yeah?
 
  • #14
If you know a negative value, add 360 since the sine and cosine functions are periodic over 360 degrees. You need to know the form of the sine function to figure out the angles quickly. Since sine goes from 0 to -1 in the third quadrant and from -1 to 0 in the fourth, angles which are equally distant from 180 and 360 have equal sines. For example, 180+30=210 and 360-30=330. Similarly 180+45=225 and 360-45=315 have the same sine.
 
  • #15
Yes, they have the exact same line. So, does it make any difference if let's say i keep a value at sin135 or sin45, aside for showing that i know that these values are equivelent?
 
  • #16
Does that mean cos can have 3 types of values?

Lets say cos is 85. cos85.

then i can do 360-85 and get cos275.

then cos 275-180 =cos95

and if i do -cos95 i can get the exact same value...
 
  • #17
Basically if you draw vertical lines on the unit circle, the cosine is the same, and if you draw horizontal lines, the sine is the same. If you add 360 to an angle, you will get the same value for any trigonometric ratio.
 
  • #18
How do you convert a decimal, like 0.3061 into a radical.

18a) Find the exact value of each of the following.

a) sin 30*sin45*sin60

I got 0.3061 as the decimal, how do i turn that into a radical? I used the calculator to solve, and the exact triangles. :S
 
  • #19
Nelo said:
a) sin 30*sin45*sin60

I got 0.3061 as the decimal...
Interesting. I got about 0.2563. We're evaluating
sin (30 rad) * sin (45 rad) * sin (60 rad)
after all. :rolleyes:

Oh, you mean DEGREES? Then for goodness sake, write in the degree symbol!

Nelo said:
I got 0.3061 as the decimal, how do i turn that into a radical? I used the calculator to solve, and the exact triangles. :S
You don't. You evaluate the 3 sine expressions separately to get their exact values, and then multiply the fractions together.
 
  • #20
You need to know the exact values of sine and cosine at 0,30,45,60 and 90 degrees at least for trigonometry.
 

1. What is a word problem involving trigonometric functions?

A word problem involving trigonometric functions typically involves using trigonometric ratios to solve for unknown sides or angles in a given situation. For example, a common problem may involve finding the height of a building using the angle of elevation and distance from the building to a person's feet.

2. How do I approach solving a word problem with trigonometric functions?

The key to solving a word problem with trigonometric functions is to first identify the given information and what you are being asked to find. Then, use the appropriate trigonometric ratio (sine, cosine, or tangent) to set up an equation and solve for the unknown variable using algebraic techniques.

3. What are the most common trigonometric ratios used in word problems?

The most commonly used trigonometric ratios in word problems are sine, cosine, and tangent. These ratios represent the relationship between the sides of a right triangle and the angles within the triangle.

4. Can I use a calculator to solve word problems involving trigonometric functions?

Yes, a calculator can be a helpful tool in solving word problems involving trigonometric functions. However, it is important to understand the concepts and steps involved in solving the problem by hand before relying solely on a calculator.

5. How can I check my answer for a word problem involving trigonometric functions?

To check your answer for a word problem involving trigonometric functions, you can plug your solution back into the original problem and see if it satisfies the given conditions. You can also use a calculator to find the trigonometric ratio of the given angles and sides to see if they match your calculated solution.

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