Work and Charge

  • #1

Homework Statement



A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?


a.0.14 J

b.0.34 J

c.80 mJ

d.14 J

e.8.0 J


Homework Equations




See below.

The Attempt at a Solution



W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

I just wanted to know if the angle and formula that I used are correct.

Thanks.
 

Answers and Replies

  • #2
2,063
2
Yes, it's correct.
 

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