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Work and Charge

  1. Feb 7, 2007 #1
    1. The problem statement, all variables and given/known data

    A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

    a.0.14 J

    b.0.34 J

    c.80 mJ

    d.14 J

    e.8.0 J

    2. Relevant equations

    See below.
    3. The attempt at a solution

    W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

    I just wanted to know if the angle and formula that I used are correct.

  2. jcsd
  3. Feb 7, 2007 #2
    Yes, it's correct.
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