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## Homework Statement

A charge of 2.0 microC is located in a uniform electric field of intensity 4.0*10^5 N/C. How much work is required to move this charge 20 cm along a path making an angle of 60° with the electric field?

a.0.14 J

b.0.34 J

**c.80 mJ**

d.14 J

e.8.0 J

## Homework Equations

See below.

## The Attempt at a Solution

W = E*q*d*cos theta = (4.0*10^5 N/C)*(2.0*10^-6 C)*(0.2 m) *cos(60) = 0.08 J

I just wanted to know if the angle and formula that I used are correct.

Thanks.