I'm going through a few exercises on Schaum's outline college physics, the section on work and energy. It says "In general, the work done against gravity in lifting an object of mass m through a vertical distance is mgh". So they are basically saying that the work donde to lift an object is equal to mg (which is the upward force we would exert on the object) times h (which is the vertical distance). But if the object is not moving surely we would have to apply an upward force higher than mg (as mg is the weight which is acting downwards) in order to have a resultant upward force. Otherwise the sum of the forces in the y-direction would be 0 and the object will continue at rest. Will this be a book error or am I missing something out? Many thanks in advance.