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## Homework Statement

The ends of two identical springs are connected. Their un-stretched lengths Lo are negligibly small and

each has spring constant k. After being connected, both springs are stretched an amount L and their free

ends are anchored at y = 0 and x = ±L as shown . The point where the springs are connected to each

other is now pulled to the position (x,y). Assume that (x,y) lies in the first quadrant

A. What is the potential energy of the two-spring

system after the point of connection has been

moved to position (x,y). Keep in mind that the unstretched length of each spring Lo is much less

than L and can be ignored (i.e., Lo << L).

Express the potential U in terms of k, x, y, and L

## Homework Equations

Us=1/2k(deltax)^2

## The Attempt at a Solution

So this is what I did. L_o is negligible as stated in the problem. So +or- L is my original length(Xi).

In order for the junction pt 1 of the spring to go from (+or-L,0) to somewhere in the first quadrant of (x,y), a force has to be applied that moves the spring from (+-L,0) to (positive x, positive y).

So, taking both x and y into account for this equation I got:

Us=1/2k((Xf-(+or-L))+(Yf-Yi))^2-------------and Yi=0 so we can disregard that from the equation. Does this seem correct? I feel a bit lost on this problem.