A 1400kg car ascends a mountain road at a steady 60km/h. The force of air resistance on the car is 450N. If the car's engine supplies enough energy to the drive wheels at the rate of 38kW, what is the slope angle of the road?
m = 1400kg
F(air) = 450N
V=60km/h = 60000km/3600s = 16.667ms/
W(total) = 38000W
theta = ?
W(total) = K(final) - K(initial)
K = 0.5mv^2
The Attempt at a Solution
I am not sure how to start this problem, but here is my first attempt:
38000 = 0.5(1400)(16.6667^2) - 450cos(theta)
The number was not in the domain of cos. I'm stuck. Any ideas? Thanks!