(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A roller coaster car with a mass of 2000 kg is initially moving at 10 m/s (when it is at the bottom of the "loop-the-loop" portion of the roller coaster track). The loop has a diameter of 16 meters.

The combined effect of air resistance and friction is to produce an average force of 1500 N on the roller coaster car.

How far will the car have moved vertically when its speed has been reduced to 5 m/s?

2. Relevant equations

K= 1/2(mv^2)f - 1/2(mv^2)i

s=r(theta)

r/(3.14/2) = [r-(delta y)/((3.14/2)-theta)]

3. The attempt at a solution

I was able to find the change in kinetic energy to be 75,000 J.

If I could draw a picture in here I would but I have made a triangle and used the bottom equation above to set up solving for the angle that the rollercoaster would reach at its peak vertical height. However I cant come up with a formula that will hold true for all angles. Does anyone have any ideas as where to move further

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# Homework Help: Work and kinetic energy problem

Can you offer guidance or do you also need help?

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