Calculating Work and Power: Solving a Tractor Pull Problem

In summary, a tractor pulling a wagon with a force of 700N at a speed of 20.0 km/h does 8.16 x 10^6 joules of work in 3.5 minutes and has a power output of 3888.8 watts. To convert km/h to m/s, divide by 3.6.
  • #1
bob24
14
0

Homework Statement



A tractor pulls a wagon with a constant force of 700N at a constant speed of 20.0 km/h.
a) How much work is done by the tractor in 3.5min
b) What is the tractor's power output?
ANSWERS: a)8.16 x 10^6 J//b) 3888.8 watts
2. Relevant equation
P=W/t or P=Fv



The Attempt at a Solution


P=Fv
P=700N x 20.0
P=14000J

Pt=W
14000W x 210seconds=W
W=2940000J

I've been trying for over an hour now and I just can't get the answer. Any help will be greatly appreciated.
 
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  • #2
Convert km/h to m/s.
 
  • #3
rl.bhat said:
Convert km/h to m/s.

I realized it about 5 seconds before you posted haha. Thank you very much!
 

1. How do I calculate work and power in a problem?

To calculate work, you can multiply the force applied by the distance the object moves in the direction of the force. Power can be calculated by dividing work by the time it takes to do the work.

2. What is the unit of measurement for work and power?

The unit of measurement for work is joules (J) and the unit for power is watts (W).

3. What is the difference between work and power?

Work is the amount of energy required to move an object, while power is the rate at which work is done.

4. How can I determine the efficiency of a machine in a work and power problem?

The efficiency of a machine can be calculated by dividing the output work by the input work and multiplying by 100%.

5. Can work and power be negative values in a problem?

Yes, work and power can be negative values if the force and motion are in opposite directions. This indicates that the object is losing energy instead of gaining it.

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