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**1. Homework Statement**

A force F = (2.7i + 3.2j) N is acting on a particle while it travels from the point (x, y) =

(1, -1) m to the point (2, 1) m. Find the work done by the force F on the particle.

**2. Homework Equations**

W=FD and A=SqRt of Ax^2+Ay^2

**3. The Attempt at a Solution**

ok i used the right triangle to find the resultant vector of the force F by squaring both the 2.7 and 3.2 then adding them and take the square root i got 4.18 so that should be the F in W=FD and then i foudn teh reultant vector of the coordinates 1,-1 and 2,1 and got square root of 5. which should be the distance and then i multiplied 4.18 and radical 5 and got 9.34 which is wrong.. where did i go wrong? btw 9.10 is the answer