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Work and velocity

  1. Oct 19, 2007 #1
    Problem: A proton moving at 6.5x10^6 m/s encounters an electric field of 4500 volt/meter.
    How fall will the proton penetrate the field before stopping. (Electric field and proton are moving in opposite directions)

    My attempt:
    First I found the kinetic energy of the proton, then I found the force that the electric field exerted on the proton with F=Eq. The force would do the sane amount of work on the proton as the kinetic energy the proton had to make it stop so I used w=fs with w=kinetic energy and solved for s. The answer was 49m but the answer in the book is 10.49m.
    Can someone tell me where I went wrong?
     
  2. jcsd
  3. Oct 19, 2007 #2

    learningphysics

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    Your idea is right... must have been your calculations that went wrong... can you show your steps?
     
  4. Oct 19, 2007 #3
    Mass of proton = 1.67 x 10^-27
    q of proton = 1.6 x 10^19
    using ke = 1/2mv^2 kinetic energy = 3.527875 x 10^14
    using F=Eq, F=7.2 x 10^16
    W=f x s
    W/F = S
     
  5. Oct 19, 2007 #4

    learningphysics

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    I'm also getting 49m. Double check to make sure you have the question right...
     
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