1. The problem statement, all variables and given/known data A 523 kg elevator starts from rest. It moves upward for 3.79s with a constant acceleration until it reaches its cruising speed of 1.78 m/s. The acceleration of gravity is 9.8 m/s^2. Find the average power delivered by the elevator motor during the period of this acceleration. Answer in units of kW. 2. Relevant equations w = m(a+g) p = w/t 3. The attempt at a solution m = 523 a = 1.78 t = 3.79 w=m(a+g)=523(1.78+9.8)=6056.34 p=w/t=6056.34/3.79=1597.98W 1597.98W becomes 1.59798kW I was incredibly confident in this answer, but it is wrong. Where did I make my silly error?