Hey guys, I understand that if you lift an object a short distance in the air that it takes work because you are moving against the the weight of the object through a distance. So the equation in my mind is W=mgdcos[tex]\Theta[/tex] where [tex]\Theta[/tex]=0. But what I can't figure out is what if I lift the object with a force that accelerates the object F>Weight. If I lift an object with a force equal to it's weight is the work different than if I accelerate the object to the same height? I hope this makes sense.(adsbygoogle = window.adsbygoogle || []).push({});

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# Work calculations

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