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Work (Calculus II)

  1. Sep 9, 2008 #1
    "Work" (Calculus II)

    This is a problem from the chapter called "Work":

    A water tank in the form of an inverted right-circular cone is 29 ft across the top and 15 ft deep. If the surface of the water is 5 ft. below the top tank, find the work done in pumping the water to the top of the tank. Assume water weights W lbs. per cubic feet (which means your answer will be expressed in terms of W)


    I have read it many times but I don't know what to do to solve it...please help, I really appreciate it.
     
  2. jcsd
  3. Sep 9, 2008 #2

    Dick

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    Re: "Work" (Calculus II)

    Work is weight times distance. At a given distance h below the top of the tank take a slice of the water of thickness dh. The weight is volume of the slice times W. The work to pump it to the top is h*(volume of the slice)*W. Now you need to integrate that over the range of h that includes all of the water in the tank. Is that enough to get started? It's a lot like finding the volume but with those extra factors of W and h.
     
  4. Sep 9, 2008 #3
    Re: "Work" (Calculus II)

    thank you very much...i'm going to see if I can solve it using this :)
     
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