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Work Circular Motion

  1. Oct 31, 2007 #1
    1. The problem statement, all variables and given/known data
    A ball of mass 0.765 kg is tied to the end of a string of length 1.59 m and swung in a vertical circle.

    a)During one complete circle, starting anywhere, calculate the total work done on the ball by the tension in the string.

    b)During one complete circle, starting anywhere, calculate the total work done on the ball by gravity.

    c)Repeat part (a) for motion along the semicircle from the lowest to the highest point on the path.

    d)Repeat part (b) for motion along the semicircle from the lowest to the highest point on the path.





    3. The attempt at a solution

    I know that for part a and b it will be 0, because the displacement is 0, according to W = F * s

    However, I don't understand part c.

    the displacement is 4.995.
     
  2. jcsd
  3. Oct 31, 2007 #2
    what is happening to the rock?? What is occurring to its height??

    What kind of energy is being imparted to the stone as a result of this height change?

    What is the height change?
     
  4. Oct 31, 2007 #3
    what is happening to the rock?? it's moving up
    What is occurring to its height?? increasing upwards

    What kind of energy is being imparted to the stone as a result of this height change? gravity is pulling down, and tension is pulling it toward the center I believe

    What is the height change? 4.995
     
  5. Oct 31, 2007 #4
    For part c then
    what is the angle between the displacement of the rock and the force of tension?? Consider very small displacements
     
  6. Oct 31, 2007 #5
    the angle theta is 3.141509434
     
  7. Oct 31, 2007 #6
    why is that?
     
  8. Oct 31, 2007 #7
    displacement is 4.995 right? (unless this is incorrect).

    length of string is 1.59m

    4.995m = 1.59(theta)
     
  9. Oct 31, 2007 #8
    we'll talk about how you got the4.995 later.
    How do you figure theta from there??

    Think about it... the tension is pulling the rock inward. The rock is moving in a circle. If something is moving in a circle what is its instantaneous displacement?? Along what direction is the instantaneous displacement?? What is the angle between this instantaneous displacement and the force of tension??
     
  10. Oct 31, 2007 #9
    if something is moving in a circle, then the displacement would be in radians. instantaneous displacement o_O

    the direction of the instantaneous displacement is upwards.

    The angle is pi/2 or 90 degrees.
     
  11. Oct 31, 2007 #10
    Good. SO the angle between the force of tension and the displacement is zero. Hence waht is the work done by the tension?

    [tex] W = F d \cos \theta = F d \cos \frac{\pi}{2} = ? [/tex]
     
  12. Oct 31, 2007 #11
    0.

    that would be part c.

    now would part d be similar.
     
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