Hey, Rather confused about a concept with "Work". Say you're given an inclined plane problem where you're told to find the work energy required to move an object to the top of the plane (this is a TYPE of work problem, I should think). The answer (anyhow), in value is equal to the gravitational potential energy (mgh). Now... I ask. Why is that? (In other words, why isn't it the applied force (minus Fg parallel or Fg sin theta) - could you not consider finding work using the applied force PLUS using the length of the incline (hypotenuse) as delta d instead?) This problem has shown up in the past, the absolute BEST you could do is just clarify "conceptually". Or just help. Thanks!