# Work done and friction problem

1. May 26, 2010

### Brittykitty

A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is

w=fd
w=(37N)(24m)
w=888J

Does this procedure seem correct ? :) Thank you!

2. May 26, 2010

### PhanthomJay

No. You have calculated the net force and net (total) work done on the object. The total work done on the object includes the work done by the applied 52 N force, and the work done by the friction force. The work done to overcome friction is the work necessary to keep the object moving at constant velocity.

3. May 26, 2010

### Brittykitty

What formula would I use to find the work done to overcome friction? I sort of understand but am still a bit confused

4. May 26, 2010

### PhanthomJay

The work done to overcome friction while moving the block 24 m is the negative of the work done by friction while moving the block 24 m.

5. May 27, 2010

### Brittykitty

So it would be -888J?

6. May 27, 2010

### Brittykitty

24m*15N=360?

7. May 27, 2010

360 J, yes.