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Work done at an incline

  1. Mar 15, 2008 #1


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    1. The problem statement, all variables and given/known data
    object with force of 80N at 170 degrees from x-axis...
    moved of a distance of 2.2m at an angle of 10 degrees
    problem does not state exactly 10 degrees in respect to what...

    2. Relevant equations
    net force is equal to force applied in the horizontal direction (force times cosine of angle) times the distance...

    3. The attempt at a solution
    After using all my tries on this problem (WebAssign), I realized it's not 10 degrees with the applied force because it would be just simply 80cos(170)2.2...

    If I were to calculate the 10 degrees factor...how would I do it? I thought about trying 160 degrees of the applied force...but there's no way to find out the right answer because I used all my attempts...

    There's a few more I'm bound to have troubles with so I'll just continue posting...
  2. jcsd
  3. Mar 15, 2008 #2

    Doc Al

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    Staff: Mentor

    Sounds good to me.

    Since the first angle (170) was with respect to the x-axis, one would assume that's the reference for the second angle as well.
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