1. The problem statement, all variables and given/known data A man is standing on a cart of mass double the mass of man. mass of the man is m. initially the cart is at rest on a smooth ground. now, the man jumps w/ velocity v horizontally towards right wrt the cart. find the work done by the man during the process of jumping. 2. Relevant equations W = Change in kinetic energy Initial momentum = Final momentum 3. The attempt at a solution I calculated the change in kinetic energy and equated it to the work done, but i'm not able to get the right answer, which is mv^2/3.