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Work done by a spring

  • Thread starter GreenPrint
  • Start date
  • #1
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Homework Statement



http://img205.imageshack.us/img205/7536/capturebb.jpg [Broken]

i am stuck on part c

how do i find work with out using the spring constant





Homework Equations



work equals force parallel times displacement at which the force is acted during...

Work done by spring = .5 kx^2
Work = delta K

but delta K = 0 because the table top is frictionless

Work = delta U
delta U = 0 in this situation correct?

The Attempt at a Solution



so I'm stuck...

i think it might be zero but .5 kx^2 would not give zero now would it...
 
Last edited by a moderator:

Answers and Replies

  • #2
rl.bhat
Homework Helper
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The work done on the block by the spring is equal to the change in KE of the block.
 
  • #3
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hmmmmmmmm.... so then.... um.....
 
  • #4
1,196
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ok thanks
 
  • #5
1,196
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wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

???
 
  • #6
1,196
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- (Mg)/(2h)
 
  • #7
rl.bhat
Homework Helper
4,433
7
wait so to find the spring constant...

is delta U = delta K = W = .5 kx^2

???
0.5 kx^2 = 0.5 Mv^2.
From the given data you can find v.
 

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